(n+2)^2=n(n-5)+22

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Solution for (n+2)^2=n(n-5)+22 equation: 



(n+2)^2=n(n-5)+22

We move all terms to the left:

(n+2)^2-(n(n-5)+22)=0



We calculate terms in parentheses: -(n(n-5)+22), so:

n(n-5)+22

We multiply parentheses

n^2-5n+22

Back to the equation:

-(n^2-5n+22)



We get rid of parentheses

-n^2+(n+2)^2+5n-22=0

We add all the numbers together, and all the variables

-1n^2+5n+(n+2)^2-22=0

We move all terms containing n to the left, all other terms to the right

-1n^2+5n+(n+2)^2=22

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